Question
Each combination of capacitors between points $a$ and $b$ in Fig. $P 24.64$ is first connected across a $120-\mathrm{V}$ battery, charging the combination to 120 $\mathrm{V}$ . These combinationsare then connected to make the circuits shown. When the switch Sis thrown, a surge of charge forthe discharging capacitors flows to trigger the signal device. How much charge flows through thesignal device in each case?
Step 1
In the first case, the capacitors are in parallel, so the total capacitance is the sum of the individual capacitances. Therefore, we have $C_{p} = C_{1} + C_{2} + C_{3} = 10 + 20 + 30 = 60 \mu F$. Show more…
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Each combination of capacitors between points $a$ and $b$ in Fig. $P 24.64$ is first connected across a $120-\mathrm{V}$ battery, charging the combination to 120 $\mathrm{V}$ . These combinations are then connected to make the circuits shown. When the switch Sis thrown, a surge of charge for the discharging capacitors flows to trigger the signal device. How much charge flows through the signal device in each case?
Each combination of capacitors between points a and b in $\textbf{Fig. P24.60}$ is first connected across a 120-V battery, charging the combination to 120-V. These combinations are then connected to make the circuits shown. When the switch S is thrown, a surge of charge for the discharging capacitors flows to trigger the signal device. How much charge flows through the signal device in each case?
24.64. Each combination of capacitors between points a and $b$ in Fig. 24.35 is first connected across a $120-\mathrm{V}$ battery, charging the combination to 120 $\mathrm{V}$ . These combinations are then connected to make the circuits shown. When the switch $S$ is thrown, a surge of charge for the discharging capacitors flows to trigger the signal device. How much charge flows through the signal device?
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