00:01
Each copper 2 sulfate unit is associated with five water molecules and a crystalline copper 2 sulfate pentahydrate.
00:07
And that is shown in the equation here.
00:10
When the compound is heated, it loses the water molecules and its blue color according to the equation shown.
00:16
If 9 .60 grams of copper sulfate are left behind after heating 15 .01 grams of the blue compound, calculate the number of moles of water originally present in the compound.
00:30
Pound.
00:31
So we know that for every one mole of copper sulfate that you have in this hydrated molecule, you will get five moles of water.
00:46
So what we're going to assume is that this reaction went to completion, and that after the reaction happened, there were no more hydrated molecules.
00:59
They were all either copper sulfate or just water.
01:03
So what we're going to do is we are going to start with the 9 .60 grams of the copper sulfate.
01:13
And we're going to convert this to moles by saying one mole weighs 159 .60 grams...