00:01
Okay, so in this problem we have a two -n, sorry, we have two -n oscillators.
00:08
Okay, so i say that this is an oscillator because it's an electron that is free to move along the x -axis.
00:18
Therefore, we can consider this a harmonic oscillator because of the potential energy for each one of the electrons.
00:28
So i say this is an oscillator because the potential energy is one half of kx square.
00:38
Therefore, this is an harmonic oscillator in one -dimensional.
00:42
And we have two n electrons.
00:49
So we have to consider it in this problem the exclusion principle to show that the minimum energy will be the energy described the problem and how we actually is going to do this first of all let's remember what is the energy for one harmonic oscillator and let's see the energy e to the n of one harmonic oscillator is the plank constant multiplied by the frequency that multiply n which is the state of the electron plus one half.
01:34
So this is the energy of one harmonic oscillator and one dimension.
01:42
And what is the exclusion principle? well, we must remember that electrons cannot occupy the same state, the same energy state.
01:55
Therefore, when we're considering the energy state, n equals 1, for example, this state allows, two electrons, only two electrons.
02:09
And that's because we have to also consider the spin.
02:14
And the spin, which is ms, has values of plus and minus one half.
02:23
Therefore, each n quantum number allows two different electrons.
02:32
Okay.
02:32
Okay, so this is really important.
02:35
Each n allows two electrons...