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Hi, in the given problem from the chapter alcohols, ethers and thiols, some of the compounds are given.
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We have to write the structural formula for these given compounds.
00:11
The first compound given to us is isobutal alcohol.
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And this compound, the alcoholic group, is bonded to isobutile group.
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So we can represent the structural formula of this compound as shown here, ch3, ch, ch2oh.
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And this carbon, central carbon contains a methyl group bonded to it.
00:32
This structure can also be presented in the form of line angle formula as shown here where we can represent the groups in this form.
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The next molecule is 1 -3 -butane diol.
00:45
With a chain of four carbon atoms, this compound contained two hydroxyl group at carbon 1 and carbon 4 respectively.
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So the structure of this compound can be written as ch2 having oh -h -q -2.
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Group, ch2, ch2, ch2, ch2 having oh group, where this is carbon number one and this is carbon number four.
01:13
We can also represent it in the form of the line angle formula as shown here, where this first carbon has oh group and here, this fourth carbon as oh group on it to it.
01:32
Then we have the next compound, 5 methyl 1 hexanol with a chain of six carbon atoms, there is a methyl group at carbon 5 and oh h group at carbon 1 so we can represent this compound as c h 3 c h having methyl group bonded to it c h 2 c h 2 c h 3 where the numbering sorry this is c h 2 oh h where this is carbon 1 and carbon 5 has methyl group bonded to it.
02:11
The line angle formula for this structure can be drawn as shown here.
02:17
This is a carbon one which contains oh group bonded to it and this is carbon 5 containing methyl group...