a) A-left;B-right;C-left;D-left

b) A-right;B-left;C-right;D-right

c) A-left;B-right;C-left;D-left

d) They all have the same number of atoms per mole (Avogadro's constant.)

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When we look at the idea of molar Mass or Adam's program, there are different ways that we can consider this. Each of these images shows a different number of particles and different masses. And so the lower down on the skill, the more mass in each circle represents number of particles. So we can compare molar mass of each sample in a, B, C and D and Mueller, Mass is the ratio of the mass. We're grams per mole. We can also look at the ratio of the atoms per gram. So, for example, if we consider example a you can see on the left there are five circles and we'll see each one of those is a mole of particles, and it has more mass. And on the rate there are six moles with less math. So if we look at the ratio of master mole we want to see in order to have, the larger Moeller, Mass should be something that has a larger mass number. So greater math. Been a smaller number of moles because that's what will give us the largest number here. A big number on top and a small number on bottom. So If we look at these two, we can see that the one that has greater mass unless moles is the sample on the left. So the left has a greater molar Mass. If we look at Adam's per gram in orderto have a larger ratio, we would want a large number on top and a small number on bottom. So we can also consider each of these circles instead of each being a mole of a substance to be a specific Adam of a substance show. If we look for the one that has the greater number of Adams in the smaller mass, that's the one on the right. So the right has more Adams program. If we look for the one that has fewer atoms per gram, that would be the one to get. A smaller number here would have a large number on top, a small number on top and a larger number on bottom, which is our left. And finally, which one has more? The ratio of Adams Permal This is the same because of a God Rose number always tells us that one more is equal to 6.2 times 10 to the 23rd particles, so both have equal ratios of Adam's two moles. If we look at example be we can see that on the left there are more particles or more moles, but less mass. And on the right, there are less particles and more mass so we can do the same. Analysis is above the greater molar. Mass is the one that has the larger mass and less particles, So that's our right sample. The ratio of Adam's two grams to have a larger value is more Adams and Smaller Mass, which is the left on the right. We also see there are fewer Adam's program, and again, they both have the same ratio of Adam's two moles. If we look at our third example, see because he here that they both have the same number of particles, but they want on the right has less mass. So if we're looking for the one that has the greater Moeller Mass, that means the more mass her moles, which is the right more atoms per gram again, looking for a smaller mass with the same number of Adams would be on the left, and so the right would also have fewer Adams program and, again, the question of what's the ratio of Adam's two moles. They both have equal ratio of Adams two moles. The last example be has different numbers of particles, but the same mass. You conceive that on one side, on the left side there are fewer particles than on the right side. So if we consider our Moeller Mass, if they have the same mass and mass divided by moles, we want the one with fewer atoms. So the left has the greater molar mass. Thanks, considering the ratio between Adams and Graham. Since they have the same mass, the more atoms, the greater that ratio. So the right side has more atoms per gram. The left side has fewer atoms, and finally, the ratio between moles and Adams is the same.