00:02
Okay, for part a of this question, we have to write the equation for the products with beta positive emission.
00:16
We have 28, phosphor 15, undergoes beta positive emission, which decrease the atomic number by 1.
00:29
So the product formation will be 28, 14, silicon plus 0 1 beta.
00:39
The number of neutrons equals, so number of neutrons will be equal to mass number.
00:51
So mass number minus atomic number, which is 28 minus 14, equals 14, we have number of protons equals number of, sorry, we have number of protons equal atomic number, which is 14.
01:17
And so the ratio of neutron to proton, which is n by z, equal to 1 by beta positive emission...