Question
Each term of an infinite geometric progression is twice the sum of all the terms which follows it. The common ratio of this GP is(a) $\frac{1}{3}$(b) $\frac{1}{2}$(c) $\frac{1}{4}$(d) $\frac{2}{3}$
Step 1
According to the problem, each term of the progression is twice the sum of all the terms that follow it. This means that $a = 2(a*r + a*r^2 + a*r^3 + ...)$. Show more…
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