00:02
For the given problem, we need to find the pressure at the summit of the mountain at sea level.
00:11
So for part a, the pressure is modeled by the following equation.
00:17
Pz equals 1 ,000 into e, raised to the power z divided by 10, where z is height and kilometers.
00:28
At the summit, the height is going to be equal to 10 kilometers as described by the problem.
00:37
We put in the value of z in the given equation, we get 1 ,000 into e raised to the power minus 10 divided by 10, which is equal to 367 .88 millibars.
00:58
At c level, the height is equal to 0.
01:09
So p0 can be calculated at 1000 into e, raised to power 0 divided by 10, which is equal to 1 ,000 millivars.
01:24
For part b, we need to find the average change in pressure at 5 kilometers.
01:31
At 5 kilometers, the pressure can be calculated as 1000 e -raised -to -power minus 5 by 10, which can be found as 606 .53.
01:45
As we've already found that at height 0, which is c -level, the pressure is 1 ,000 milliseconds.
01:56
To find the average change, we can subtract p5 from p5.
02:05
A zero divided by the change in height...