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Earth's average surface temperature is about 287 $\mathrm{K}$ . Assuming Earth radiates as a blackbody, calculate $\lambda_{\max }$ for the Earth.

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University of Michigan - Ann Arbor

Numerade Educator

University of Washington

University of Winnipeg

Hey, so when this problem, we're told that the Earth were coming the earth's temperature. We want to get the, uh, wavelength of the black body radiation. So the temperature is to 87. Come in. And we want to use wines Displacement law to get the, uh, wavelength. So that's Lambda Max. Times t equals 0.28 nine a times 10 to the minus two Calvin meter. And we can solve for Lambda by dividing both sides by t. So plugging this into a calculator catch rise. I please. Was it to 87 of the right number 2 87? Um, with that, I got 10. How many sick Biggs? 10.1 micron micrometers.

University of Washington