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Hi there.
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So for this problem, we are told that a rate of light is incident at an angle that is equal to 30 degrees.
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And on a plain slab of flamed glass surrounded by water.
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So for part a of this problem, we are asked to find the refraction angle.
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And so when light coming from the surrounding median is incident on the surface of the glass slab, snell's law states that the index of refraption of the class times the sign of the angle of reflected is equal to the index of refraption of the surface times the sign of theta of the angle of incidence.
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So if we solve for the sign of the angle of incidence, of the angle of refraption, we're going to obtain that this is the ratio between the index of refraption times the sign of theta incident.
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Now, for the first part of this problem, we know that the angle of incidence is equal to 30 degrees.
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And the serratin median is water.
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So we know that the index of, the index of refraption for water is equal to 1.
01:39
333.
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And the angle of refraption then from this equation is going to be that this is the sign of minus 1.
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What we have done is to apply the inverse function of the sign in this equation right here.
01:57
And we substitute the value...