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Egg drop. You are on the roof of the physics building of your school, 46.0 $\mathrm{m}$ above the ground. (See Figure $2.53 . )$ Your physics professor, who is 1.80 $\mathrm{m}$ tall, is walking alongside the building at a constant speed of 1.20 $\mathrm{m} / \mathrm{s} .$ If you wish to drop an egg on your professor's head, where should the professor be when you release the egg, assuming that the egg encounters no appreciable air drag.

$=3.6 \mathrm{m}$

Physics 101 Mechanics

Chapter 2

Motion along a Straight Line

Physics Basics

Motion Along a Straight Line

Motion in 2d or 3d

Newton's Laws of Motion

Cornell University

University of Michigan - Ann Arbor

Simon Fraser University

University of Winnipeg

Lectures

03:28

Newton's Laws of Moti…

04:16

In mathematics, a proof is…

02:41

Egg Drop. You are on the r…

01:42

You are on the roof of the…

05:43

An egg is thrown nearly ve…

04:35

08:24

01:31

An egg drops from a second…

03:34

02:18

Standing on the ground $3.…

02:29

A student throws a water b…

01:02

In an egg-dropping contest…

01:48

06:08

04:43

Free-Fall Acceleration…

09:51

An object of mass $m$ is d…

0:00

A parachutist is in free f…

13:45

You're staring idly o…

06:30

A flowerpot is knocked off…

05:30

You and your roommate plot…

28:42

A 12.0-kg shell is launche…

03:26

\bullet A balloon carrying…

Let's stake positive. I Toby upward So the egg has an initial velocity zero. Let's say it starts from hide it So I know it is equal to EJ on DH it drops So final ly is Siegel on DH Acceleration is negative 9.8 meters per second squared because positive eyes taken Toby upward. And we know that acceleration due to gravity is dollar word. So there should be a negative sign now the distance. So find the distance. The professor walks during the time d it takes the egg to fall to fall So the height off his head when which we took as zero. So we took the height. Toby got to be the reference point. Now, at this height, which is it? It is in fact, Ricardo, why not minus life quarto edge. And this is given Toby 44.2 meters. Now, to find the time, we will pick a question that involves all of these parameters along with de which we long to find out. So you will lose this equation for that on this gives negative at to be equal to half off a white T's great so as you can see here. Why not? Minus y is at So why minus? Why not will be negative. It's This term's goes away because initial velocity is sealed off. So we have a saying to be equal to negative off twice off it over a while we have to take the report. And if we if you saw this you find this value, Toby. Two seconds. So you should get this fellow Toby positive if your directions are right. So as you can see, acceleration is negative. So that negative sign and the one over here cancels out and you need to take the positive route over. Dagestan's should be positive and on it should come out of the three seconds now the professor walks a distance x minus X Not so to find this, we can use the same question over here. But now the song that for the heart is on the election and we know that there is no acceleration, the horizontal direction So x is Cedo on DH. Be not X is 1.2 meters per second. So this means that the distance traveled by the prophecy is equal to re not. X TV will use the value ofthe time that we found here. So this gives to a point six meter could be the distance. So you should release the egg when your prophecy is 3.6 meter from the point directly below you.

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