00:01
Something that says our demand function q is in the form mp plus b.
00:05
One thing to look at is this is in the same form as y y equals m x plus b which is the slope of a line so that what this tells you is that we have a q that is acting as a y and a p that is acting as an x.
00:24
So when we draw a graph here we can label our y -axis as a q axis and our x -axis as a p -axis.
00:35
M is the slope, b is the y intercept.
00:38
The b is greater than zero.
00:40
So a b greater than zero means we're going to have a b somewhere over here.
00:45
We do know that much.
00:47
We know our slope is negative.
00:49
So we know that our line, q equals mp plus b, has an intercept at b that's positive and a negative slope down.
01:00
So we need to find our y intercept, which we kind of already know is b, as well as our x intercept right here.
01:10
So we know our y intercept, so y or q intercept, where it crosses the q axis is b.
01:18
But we need this down here.
01:20
So this, our q is going to be equal to 0, is equal to mp.
01:28
Plus b because on the p axis there's no q so we can set it equal to zero we have negative b is equal to m p so negative b over m is equal to p so we have negative b over m now the other thing to keep in mind here is that b is greater than zero so this is a negative number but m is less than zero so p is greater than zero all the time because you have a negative positive number.
02:03
So b could be five, but negative five divided by a slope that's less than zero, negative 10, is going to be a positive p.
02:11
So p is always going to be greater than zero.
02:13
So having our graph over here makes sense.
02:16
So what we have is we have a line with a negative slope that intercepts the q axis.
02:27
This is the q axis at b and interseps.
02:32
The p axis at negative b over m.
02:39
Okay, so now that we have that, we can write these as coordinate points.
02:44
Our coordinate points are 0 comma b, and we have the points negative b over m comma 0...