00:01
Okay, so the question was asking us to determine the diaport charge for this question.
00:07
Okay, so we know since you want us to make sure the diapel charge can induce an initial acceleration of 1 .0 meter per second square, that means the net force.
00:20
We know the net force is equal to f -net is equal to ma, okay? and we know a is equal to 1 .0 meter per second square.
00:33
And this can be equal to kqq over r1 square plus kq over r2 square and then minus the friction.
00:52
Kq over r1 is the electric force from the left side of the station which consists with a positive charge.
01:00
And kqq over r2 square is the electric force from the right side station, which was considered with negative charge, so it will produce a attractive force, okay? and minus the friction, because if we consider the electric force is in the right direction, okay? that means the friction, which always is always trying to oppose the motion of the train, is in the negative direction, okay? so we have such equation here, and our question was to determine the charge capital q.
01:35
Well, let's see how to determine that.
01:38
So we have m .a...