00:02
Let's consider the cross -sectional area of a wire of a certain length not drawn to scale just done like that so it's easier to perceive so we are given the cross -sectional area one seven meters squared the length is equal to 12 feet the length of this wire there's a current traveling through this wire at 5 .0 ampiers the resistivity this is not given in the question however, if you look it up in a table in the back of your book, you should find that the resistivity of copper is 1 .68 times 10 to the negative 8 meters.
01:08
By convention, we're given resistivity in that particular set of units, but we need to consider both cross -sectional area and length.
01:18
So to do this, we take our resistivity times length over area.
01:28
I just think about the units here.
01:30
Length is in meter units.
01:32
A is in area, is a meter squared resistivity.
01:38
That is in ome meters.
01:43
So units cancel out for meters, but you'll be lucky with oms.
01:50
Now, if we know that, let's go ahead and rewrite.
01:56
Resistance over here.
02:01
If you know that this is the resistance, we are given the current equals 5 .0 ampers.
02:11
Now what kind of information do we want to find with all this nonsense? and the answer is we want the voltage drop, which is just another way of saying the change in voltage across this wire.
02:25
So i presume you recall a lot.
02:31
So we have r and i.
02:39
I realize that.
02:40
But we'll solve it.
02:45
Here we go...