00:01
In this case, we are given the resistance of the body is 10 kohm and the voltage applied across it is 14 kilovol.
00:10
Now, if the internal resistance is 2 ,000 oom, which is 2 kilo -on, then the total resistance is simply the sum of the two resistances, which is 10 kilo -oom plus 2 -kilome, which is 12 -koum.
00:33
Now, current will simply be voltage by resistance, which is 14 kilo -oom, which is 14 into 10 cube, divided by 12 kilo, i'm sorry, 14 kilo -volt, divided by 12 kilo -oom, which is 12 times 10 -cube oom.
00:50
We can see that this is 1 .17 amperors.
00:55
Now, for part b, we want to find out the power dissipated.
00:59
Power is simply i squared r where r is the resistance of the body.
01:07
That is simply 1 .17 squared times the resistance of the body, which is 10 kilo -hom, which is 10 times 10 cubed, which gives us 13 .7 kilojoules.
01:27
For part c, we want to have the maximum current that passes through the this circuit be 1 million a.
01:39
For that, we need the resistance to be v by i, where i is the maximum current...