00:01
Hi, so to solve for this, let us write first the balance equation for this reaction.
00:07
If we have h2o forming hydrogen gas and o2, we need to balance this first.
00:14
We'll write 2 in here so that we'll have equal number of oxygen on both sides of the equation.
00:20
So that means we need to write here 2.
00:23
So that's it, that's the balance equation.
00:26
And solving for the first question, let's use black for this.
00:35
Theoretical yield, t -y, the mass of hydrogen gas using stoichiometry.
00:42
If you have 36 .0, this is grams of h2o, convert to moles by dividing the molar mass of water, 18 .02 grams here, and then moles of h2o in the numerator.
00:54
And as per balance equation, for every 2 moles of water reacted, it will form 2 moles of hydrogen gas.
01:01
So write that here, 2 moles of h2o will form 2 moles of h2.
01:10
And then we will multiply the molar mass of h2, that's 2 .02 grams here, and then moles in the denominator...