00:01
Well, in this question, we have a electromagnetic wave that has a center wavelength of 632 .8 nanometers.
00:13
And they say that the wavelength width is 0 .01 nanometers.
00:19
And they want to know what is the frequency width.
00:22
So to know the frequency wave, first need to know how to obtain the frequency from the wavelength.
00:29
So this is just the frequency of the wave is the speed of the wave divided by the wavelength because we are dealing with electromagnetic wave, speed of the wave is fee.
00:42
So we just need to know what is the maximum and minimal wavelength, and then we can find what is the maximum and minimal frequency, and then we find delta f.
00:54
So let's do this.
00:55
So lambda plus.
00:59
Is the maximum wavelength in this packet here is lambda central plus delta lambda over 2 and lambda minus is lambda central minus delta lambda over 2 and just adding this values here we obtain that lambda plus is 632 0 .81.
01:34
And nanometers and lambda minus is 632 .79 nanometers...