00:01
In this question, we have to draw loose structure of beryllium chloride using only single bonds.
00:09
And then what other resonance forms are possible that satisfied octet rule? and then which form is most important in describing b .c .l.
00:23
Okay.
00:24
For b .c .l .2, let's count the valence electrons.
00:27
Berylium has two valence electrons and each chlorine atom has seven valence electrons so seven times to 14 total 16 valence electrons now for the first one we have to draw all the single bonds so berylium in the middle and chlorine two chlorine in two corners let's put one two three four we have 12 more valence electrons and we have to make all single bonds.
01:01
So we'll put here six, one, two, three, four, five, six, and for the chlorine, another six.
01:08
So we are using all six, 16 valence electrons and all single bonds.
01:16
Here, chlorine has all eight electrons.
01:20
Each chlorine has all eight electrons, but berylium has only four electrons.
01:26
So this form, does not satisfy, does not satisfy octet rule.
01:38
Okay, now the next portion we will draw other forms where octet rule is made.
01:49
Now let's put beryllium here, two chlorine atoms in two corners.
01:55
And here, in order to meet the octet rule, beryllium should have eight electrons.
02:01
1, 2, 3, 4, 5, 6, 7, 8.
02:08
We have 16 valence electrons.
02:11
8 electrons are used up.
02:14
Then we'll put 4 with this chlorine atom and 4 with this one.
02:21
Okay.
02:23
And in this way, beryllium has formal charge.
02:27
Let's count it.
02:28
Formal charge on beryllium.
02:32
Formal charge formula is number of valence electrons.
02:36
Berrium has two valence electrons minus the non -bonding electrons here it is 0 and the bonding electrons total is 8 divided by 2...