00:01
In this question, we are going to find the absolute maximum and minimum of f, which is x multiplied by e to x or 2 1 interval from negative 3 to 1.
00:16
So first we take the relative of f.
00:20
By using product rule, we got the f prime is this.
00:26
And then we set it equal to 0 to get a critical number.
00:32
So after the calculation we got x equal to 2, negative 2 is a critical number.
00:40
And then we need to determine at x equal to negative 2 is y maximized or minimized.
00:49
So in order to do that, we need to pick up two numbers.
00:54
One is smaller than negative 2, and one is greater than negative 2.
01:01
So i picked 0 and negative 5 over 2...