00:01
So in this case, we have a 200 gram block of aluminum and 50 grams of water, which start at 100 degrees celsius and to 20 degrees celsius respectively.
00:10
And they reach an equilibrium temperature while being in an isolated system.
00:16
So no heat has been transferred to an external system.
00:20
So we want to find out the final temperature, which will call t.
00:25
Notice that i've called the initial temperatures of aluminum and water, t1 and t2.
00:30
Now, we know that the heat lost from aluminum goes into water.
00:36
So we know that m1c1, which is the mass of aluminum, times the specific heat of aluminum, times delta t, which is a change in temperature of aluminum, which would be t2, t1, which would be t2, which would be 0.
00:59
Solving this equation, we can see that the final temperature key is m1, c1, t1, plus m2, c2, d2, divided by m1c1 plus m2 c2.
01:11
And that is it.
01:12
We simply plug in our values.
01:16
M1 is 200 grams, so that's 0 .2 kilograms...