00:01
So in this problem, we know that the process is a cycle and the bc part is an adiabatic.
00:14
So let's look at it.
00:18
We know the pressure and volume at point b and we know the volume at point c.
00:25
And because b .c is an adabat, we can find the pressure at point c.
00:31
We'll do that by writing down our adiabatic formula.
00:34
The pbvv bar gamma is equal to pcvc vc par gamma.
00:38
Rearranging this, we can see that pc is equal to bb by vc par gamma times pb.
00:44
And we'll simply substitute our numbers.
00:46
We know that vc is 8 vb.
00:48
We'll substitute that and we know the value of pb.
00:51
Pb is 10 atmospheres and remember that one atmosphere is 1 .01 times 10 power 5 pascals.
00:57
So you multiply that by 10 and you get 1 .01 times 10 par 6 pascal.
01:02
And this number, remember that you can cancel vv, and this number turns out to be 3 .167 times in par 4 pascal.
01:11
This is p .c, which is equal to pa...