Question
Equation of the directrix of the parabola $4 y^{2}+12 x-12 y+39=0$ is(a) $\mathrm{x}=\frac{-7}{4}$(b) $y=\frac{3}{4}$(c) $x-y=0$(d) $2 x-3 y=0$
Step 1
The given equation is $4 y^{2}+12 x-12 y+39=0$. We can rewrite this as $4 y^{2}-12 y=-12 x-39$. Show more…
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