Question
Equation of the projection of the line $8 x-y-7 z=8, x$ $+y+z=1$ on the plane $5 x-4 y-z=5$ is(A) $\frac{x-1}{1}=\frac{y}{2}=\frac{z}{-3}$(B) $\frac{x}{1}=\frac{y-1}{2}=\frac{z}{-3}$(C) $\frac{x}{1}=\frac{y}{2}=\frac{z-1}{-3}$(D) $\frac{x}{1}=\frac{y+1}{-2}=\frac{z+1}{3}$
Step 1
We can write these lines in the form of $ax + by + cz = d$ as $8x - y - 7z = 8$ and $x + y + z = 1$. Show more…
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