00:01
Hello.
00:02
So today we're going to take a given function and a specified point and we're going to use the alternative definition for finding the slope to find the slope of the function at the specified point as well as the equation of a tangent line at that point so you see that i provided the alternative definition to the right and right off of that we are going to take our a and set that equal to our given x not and the point which is one in this case because the point is just x not and why not? so then we have x cubed.
00:40
So using this for our function, we have 1 plus h squared, or cubed, and then we have minus 1 cubed, all over h, and the limit as h goes to 0.
00:59
Well, 1 plus h cubed, you might not be familiar with this expansion, so let's break it down to things we know.
01:04
So we've already done an example where we have 1 plus h squared.
01:10
So let's take this and break it down into 1 plus h squared times 1 plus h.
01:16
And that would be to the first power because when you have a something that is cubed, you can actually break it down to three parts such that it is 1 plus h times 1 plus age times 1 plus h.
01:35
So now it's looking a little more.
01:37
Straightforward, something we can deal with, something that's manageable.
01:41
So if we just focus on this part right here, we'll solve that first, or expand it first.
01:48
So one times one is one, and then one times h is h, h times h times h, so we have a two h, then h times h is squared.
01:59
So that's our first part, and then we can multiply this, and i like to put that on the smaller component on the left side.
02:06
It's easier for me.
02:07
So, so 1 times 1 is 1, 1 times 2h, 2h, 1 times h squared, then we have h times 1, which is h, h times 2h, which is 2h squared, and then h times h squared, which is h cubed.
02:25
So that is actually our expanded version of that, and we have minus 1.
02:30
So the 1s cancel, and then if we simplify that numerator, i like to start with the highest exponent...