Equilibrium constant for the reaction H2 O(g)+CO(g) ⇌H2( g)+CO2( g) is 81 . If the velocity cons

Name: Problem 85, Chapter 7: A Complete Resource Book in Chemistry for JEE Main 2018
Uploaded: 2021-10-14T05:58:29-08:00
Duration: 2 min 30 s
Channel: Preeti Kumari
Description: Equilibrium constant for the reaction H2 O(g)+CO(g) ⇌H2( g)+CO2( g) is 81 . If the velocity constant of the forward reaction is 162 L mol^-1 sec^-1, what is the velocity constant (in L mol^-1 sec^-1 ) for the backward reaction? (a) 13122 (b) 2 (c) 261 (d) 243

step 1 In this problem, we have given that equilibrium constant denoted by kEQ for a particular reactio

Question

Equilibrium constant for the reaction $\mathrm{H}_2 \mathrm{O}(\mathrm{g})+\mathrm{CO}(\mathrm{g}) \rightleftharpoons \mathrm{H}_2(\mathrm{~g})+\mathrm{CO}_2(\mathrm{~g})$ is 81 . If the velocity constant of the forward reaction is 162 L $\mathrm{mol}^{-1} \mathrm{sec}^{-1}$, what is the velocity constant (in $\mathrm{L} \mathrm{mol}^{-1}$ $\mathrm{sec}^{-1}$ ) for the backward reaction? (a) 13122 (b) 2 (c) 261 (d) 243

    Equilibrium constant for the reaction $\mathrm{H}_2 \mathrm{O}(\mathrm{g})+\mathrm{CO}(\mathrm{g}) \rightleftharpoons \mathrm{H}_2(\mathrm{~g})+\mathrm{CO}_2(\mathrm{~g})$ is 81 . If the velocity constant of the forward reaction is 162 L $\mathrm{mol}^{-1} \mathrm{sec}^{-1}$, what is the velocity constant (in $\mathrm{L} \mathrm{mol}^{-1}$ $\mathrm{sec}^{-1}$ ) for the backward reaction?
(a) 13122
(b) 2
(c) 261
(d) 243

A Complete Resource Book in Chemistry for JEE Main 2018

A.K. Singhal 3rd Edition

Chapter 7, Problem 85

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Solved by Expert Preeti Kumari

10/14/2021

Step 1

We have the equilibrium constant $ K $ for the reaction: \[ \mathrm{H}_2 \mathrm{O}(\mathrm{g}) + \mathrm{CO}(\mathrm{g}) \rightleftharpoons \mathrm{H}_2(\mathrm{g}) + \mathrm{CO}_2(\mathrm{g}) \] The equilibrium constant $ K $ is given as 81, and the Show more…

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Equilibrium constant for the reaction $\mathrm{H}_2 \mathrm{O}(\mathrm{g})+\mathrm{CO}(\mathrm{g}) \rightleftharpoons \mathrm{H}_2(\mathrm{~g})+\mathrm{CO}_2(\mathrm{~g})$ is 81 . If the velocity constant of the forward reaction is 162 L $\mathrm{mol}^{-1} \mathrm{sec}^{-1}$, what is the velocity constant (in $\mathrm{L} \mathrm{mol}^{-1}$ $\mathrm{sec}^{-1}$ ) for the backward reaction? (a) 13122 (b) 2 (c) 261 (d) 243

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Key Concepts

Relationship Between Equilibrium and Rate Constants

For reversible reactions, the equilibrium constant is determined by the ratio of the forward reaction rate constant to the reverse reaction rate constant. This relationship bridges chemical kinetics and thermodynamics by linking the rates at which reactants convert to products and vice versa with the position of equilibrium.

Equilibrium Constant

The equilibrium constant (K) quantifies the ratio of the concentration of products to reactants at equilibrium for a given reaction. It is temperature-dependent and indicates the extent to which a reaction will proceed toward products under equilibrium conditions.

Rate Constant

A rate constant is a proportionality factor in the rate law of a chemical reaction that relates the reaction rate to the concentrations of reactants. Its value reflects the speed of the reaction and is specific to a given temperature and reaction pathway.

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