00:01
Okay, so here we have a velocity function, t times 25 minus t squared to the fiber of one half over the interval zero to five.
00:09
What we want to do is figure out a constant velocity that if we go over the same interval, we'll go the same distance as this velocity function.
00:21
So to do that, we're going to integrate this from 0 to 5, 25 minus t squared, 1 1⁄2, which is, of course, equal to.
00:31
So because we have a t squared here, we're going to divide the whole thing by negative 2t 25 minus 2 squared.
00:42
We're going to have 3 over 2.
00:44
So we're going to divide it by 3 over 2 as well.
00:46
So this is going to be times 3.
00:48
There's going to be times 2.
00:50
So we get 2 t cancels, 2 t cancels, and we get 25, negative 25 minus t squared to power 3 over 2 divided by 3.
01:09
From 0 to 5.
01:11
If we calculate this out, 25 minus 5 squared, 3 over 2 over 3.
01:20
No, 25 minus 5 squared is 25 minus 25.
01:22
So this whole thing becomes 0...