Question
Equivalent thermal conductivity of system is(a) $1.4 \times 10^{-2}$ units(b) $1.64 \times 10^{-2}$ units(c) $1.32 \times 10^{-4}$ units(d) None
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The SI unit of thermal conductivity is (A) $\mathrm{Js}^{-1} \mathrm{~m} \mathrm{~K}^{-1}$ (B) $\mathrm{J} \mathrm{sm}^{-1} \mathrm{~K}^{-1}$ (C) $\mathrm{Jsm}^{-1} \mathrm{~K}$ (D) $\mathrm{Js}^{-1} \mathrm{~m}^{-1} \mathrm{~K}^{-1}$
The equivalent conductivity (in $\Omega^{-1}$ $\mathrm{cm}^{2} \mathrm{eq}^{-1}$ ) of $1.0 \mathrm{M}-\mathrm{H}_{2} \mathrm{SO}_{4}$ solution of specific conductance $2.6 \times 10^{-1} \mathrm{~cm}^{-1}$, is (a) $1.3 \times 10^{2}$ (b) $6.5 \times 10^{1}$ (c) $1.3 \times 10^{-1}$ (d) $2.6 \times 10^{2}$
Electrochemistry
Exercises I
A body of length $1 \mathrm{~m}$ having cross-sectional area $0.75 \mathrm{~m}^{2}$ has thermal conductivity $6000 \mathrm{~J} / \mathrm{s}$ then the temperature difference if $\mathrm{K}=200 \mathrm{Jm}^{-1} \mathrm{~K}^{-1}$, will be : (a) $20^{\circ} \mathrm{C}$ (b) $40^{\circ} \mathrm{C}$ (c) $80^{\circ} \mathrm{C}$ (d) $100^{\circ} \mathrm{C}$
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