We can factor this using the formula for the sum of cubes, which is $a^3 + b^3 = (a+b)(a^2 - ab + b^2)$. Here, $a = \sin\theta$ and $b = \cos\theta$. So, we can rewrite the numerator as:
$$
\sin ^{3} \theta+\cos ^{3} \theta = (\sin\theta + \cos\theta)(\sin^2\theta
Show more…