00:02
We are going to prove that the sine of theta plus cosine of theta over the cosine of theta minus the sine of theta minus the cosine of theta over the sign of theta is equal to secant theta times the co -sicant of theta.
00:48
Now, the first thing we're going to have to do is notice that on the right i have a single term, and on the left i've got these two fractions.
00:58
So our best bet at this point would be to try to combine these two fractions.
01:04
So to do that, we're going to need a common denominator.
01:09
So the first thing we're going to do is multiply the fraction on the left by sine theta over sine theta.
01:25
And then the one they're right by cosine of theta over the cosine of theta.
01:31
When we do that, we are going to get sine square theta plus sine theta cosine of theta over sine theta cosine of theta minus.
01:58
And on this side, when we distribute the cosine, we're going to get sine of theta, cosine of theta minus cosine square theta.
02:10
And that is over sine theta cosine of theta.
02:18
So now we've got both fractions written so that they're over a common denominator.
02:22
The next thing we're going to do is combine the two fractions.
02:27
Now be careful with their subtracting here...