Question
Estimate $\mathscr{E}^{\circ}$ for the half-reaction$$2 \mathrm{H}_{2} \mathrm{O}+2 \mathrm{e}^{-} \longrightarrow \mathrm{H}_{2}+2 \mathrm{OH}^{-}$$given the following values of $\Delta G_{i}^{\circ}$$$\begin{aligned}\mathrm{H}_{2} \mathrm{O}(l) &=-237 \mathrm{~kJ} / \mathrm{mol} \\\mathrm{H}_{2}(g) &=0.0 \\\mathrm{OH}^{-}(a q) &=-157 \mathrm{~kJ} / \mathrm{mol} \\\mathrm{e}^{-} &=0.0\end{aligned}$$Compare this value of $\mathscr{E}^{\circ}$ with the value of $\mathscr{E}^{\circ}$ given in Table $18.1 .$
Step 1
This is given by the sum of the Gibbs free energy of formation of the products minus the sum of the Gibbs free energy of formation of the reactants. In mathematical terms, this is represented as: $$ \Delta G^{\circ} = \sum \nu_{i} \Delta Show more…
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Estimate $\mathscr{E}^{\circ}$ for the half-reaction $$2 \mathrm{H}_{2} \mathrm{O}+2 \mathrm{e}^{-} \longrightarrow \mathrm{H}_{2}+2 \mathrm{OH}^{-}$$ given the following values of $\Delta G_{\mathrm{f}}^{\circ} :$ $$\quad\quad\quad \mathrm{H}_{2} \mathrm{O}(l)=-237 \mathrm{kJ} / \mathrm{mol}$$ $$\mathrm{H}_{2}(g)=0.0$$ $$\quad\quad\quad \mathrm{OH}^{-}(a q)=-157 \mathrm{kJ} / \mathrm{mol}$$ $$\quad \mathrm{e}^{-}=0.0$$ Compare this value of $\mathscr{E}^{\circ}$ with the value of $\mathscr{E}^{\circ}$ given in Table 18.1
Estimate $\mathscr{E}^{\circ}$ for the half-reaction $$ 2 \mathrm{H}_{2} \mathrm{O}+2 \mathrm{e}^{-} \longrightarrow \mathrm{H}_{2}+2 \mathrm{OH}^{-} $$ given the following values of $\Delta G_{\mathrm{f}}^{\circ}$ $$ \begin{aligned} \mathrm{H}_{2} \mathrm{O}(l) &=-237 \mathrm{kJ} / \mathrm{mol} \\ \mathrm{H}_{2}(g) &=0.0 \\ \mathrm{OH}^{-}(a q) &=-157 \mathrm{kJ} / \mathrm{mol} \\ \mathrm{e}^{-} &=0.0 \end{aligned} $$ Compare this value of $\mathscr{E}^{\circ}$ with the value of $\mathscr{E}^{\circ}$ given in Table 17-1.
Use the $\Delta H_{\mathrm{rxn}}^{\circ}$ values of the following reactions: $$\begin{aligned}2 \mathrm{SO}_{2}(g)+\mathrm{O}_{2}(g) & \rightarrow 2 \mathrm{SO}_{3}(g) & \Delta H_{\mathrm{rsn}}^{\circ} &=-196 \mathrm{kJ} \\\frac{1}{4} \mathrm{S}_{8}(s)+3 \mathrm{O}_{2}(g) & \rightarrow 2 \mathrm{SO}_{3}(g) & \Delta H_{\mathrm{rxn}}^{\circ} &=-790 \mathrm{kJ}\end{aligned}$$ to calculate the $\Delta H_{\mathrm{rxn}}^{\circ}$ value of this reaction: $$\frac{1}{8} \mathrm{S}_{\mathrm{g}}(s)+\mathrm{O}_{2}(g) \rightarrow \mathrm{SO}_{2}(g) \quad \Delta H_{\mathrm{ran}}^{\circ}=?$$
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