00:01
This is problem 147 from chapter 11, and we are trying to find the distance in nanometers between molecules of water vapor and for liquid water.
00:13
So we are going to solve for water vapor first, and the first thing we're going to do before we can do that is going to solve for the moles of this, or the liters for molds.
00:29
This is derived from the equation pv is equal to nrt.
00:39
And so it's going to be written as volume over moles is equal to gas constant, as temperature over pressure.
01:06
Okay.
01:12
Let's go ahead and plug in these numbers.
01:15
So we have 0 .082 .06 we just turn atmosphere per mole times kelvin.
01:22
This is a gas constant and this is going to be multiplied about the temperature in kelvin.
01:28
If it is 100, so i add 273 for the temperature in kelvin so 3173 kelvin.
01:38
This is going to be over the pressure with that one atmosphere and this is going to come out to be 30 .6 liters per mole.
01:59
Okay, now we can find the volume occupied by each molecule.
02:09
So, you have a 30 .6 per mole, and now we're going to transform that into how many molecules are, so 30 .6 liters per mole.
02:31
And this is going to be multiplied, but how many moles are? in the molecules are in one mole, which is another word for avogadro's number...