Question
Estimate the drawing force required to reduce the diameter of a $0.125^{\prime \prime}$ aluminum rod by $50 \%$ in a wire-drawing operation.
Step 1
First, we need to find the initial and final cross-sectional areas of the rod. Initial diameter (D1) = 0.125 inches Final diameter (D2) = 0.5 * 0.125 = 0.0625 inches Initial cross-sectional area (A1) = π * (D1/2)^2 = π * (0.125/2)^2 = 0.01227 square inches Final Show more…
Show all steps
Your feedback will help us improve your experience
Hubert Agamasu and 50 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Estimate the force needed to puncture a 0.5-cm-thick sheet of aluminum with a 1-cm diameter rivet.
A shearing force of 50 N is applied to an aluminum rod with a length of 10 m, a cross-sectional area of 1.0 x 10^-5 m^2, and a shear modulus of 2.5 x 10^10 N/m^2. As a result, the rod is sheared through a distance of: zero 2.0 cm 2.0 mm 20 cm 2 m
When a mass of 25 kg is hung from the middle of a fixed straight aluminum wire, the wire sags to make an angle of 12$^{\circ}$ with the horizontal as shown in Fig. 9-83. Determine the radius of the wire. FIGURE 9–83 Problem 65. (Figure can't copy)
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD