Estimate the rate of the reaction, $$ \mathrm{H}^{+}(a q)+\mathrm{OH}^{-}(a q) \longrightarrow \mathrm{H}_{2} \mathrm{O} $$ given the rate law for the reaction is$$\text { rate }=\left(1.3 \times 10^{11} \mathrm{~L} \mathrm{~mol}^{-1} \mathrm{~s}^{-1}\right)\left[\mathrm{OH}^{-}\right]\left[\mathrm{H}^{+}\right]$$ for neutral water, where $\left[\mathrm{H}^{+}\right]=1.0 \times 10^{-7} M$ and $\left[\mathrm{OH}^{-}\right]=1.0 \times 10^{-7} M$