00:01
All right, so for this one, we're trying to find the equilibrium constant k for at 655 kelvin for some reactions that we looked at earlier in problem 74.
00:17
And so we'll start with the first reaction, which is 2n02 going to n204.
00:34
And so the first thing i would do is think back to how do we calculate.
00:42
The equilibrium constant k.
00:44
And so you look at this formula, delta g equals delta g not plus r t ln of k.
01:00
And so we can calculate delta g not and we can also estimate delta g if we know delta h not and delta s not and r is a constant and then t is 655.
01:12
So from there, once we find delta g not and delta g we can get what k is by solving the algebra.
01:18
And so that's what we'll do.
01:20
So to find delta g not, you do delta g of formation of the products minus delta g of formation of the reactants, accounting for the molar ratios.
01:32
So you can find these values in your textbook.
01:35
I'm just going to write them down 99 .8 minus 2 times 51 .3.
01:46
And that equals minus 2 .8 kilojoules.
01:49
So let's find delta h not using the same process of 9 .16 minus 2 times 33 .2 equals minus 57 .24 kilojoules.
02:16
And we'll do delta s up here real quick.
02:19
Delta s not equals 304 .4 .4 minus two times.
02:30
240 .1 and that comes out to be if you convert to kilojoules it's minus 0 .1758 kilojoules per kelvin of values so we can plug in and find out estimate what delta g is so delta g is approximately delta h0 minus 655 which is a temperature times delta s not and so if you plug those values in you'll get approximately 57 .9 and so from here we can solve the equation to find the equilibrium constant k so 57 .9 and that's in kilojoules equals minus 2 .8 plus the constant which in kilojoules is 0 .008 314 kilogels per mole kelvin times 655 times the natural log of k.
04:10
And so we can just solve for this and so we end up getting 60 .7 equals 5 .45 natural log of k.
04:25
If you raise both powers to e, k equals 6171 .2...