00:01
Problem number 42, r equals negative 67 power 1 over 3, which means that r power 3 equals negative 67, which means that r plus 67 equals 0.
00:24
To approximate the root r of the given function, f, and the initial approximation x note, we use the newton's method.
00:31
The formula that we use for this is x.
00:35
N plus 1 equals xn minus f of x m over f dash of x n in our case f of x equals x power 3 plus 67 and f dash of x is equal to 3x power 2 and x node equals negative 3 .9 we should stop calculating approximations when two successive approximations agree to five digits to the right of the decimal point after rounding.
01:12
Now let's draw a table to help us in the iteration process.
01:32
Okay, so the initial step, x note equals negative 3 .9.
01:48
F of x equals 6 .6, 7 .69, 7 .681, sorry, 45 .63, negative 4 .0606, 833...