00:01
For part a, let's first start by writing the balanced equation for the combustion of liquid ethanol in air.
00:10
So ethanol is a chemical formula.
00:16
C2h5oh, what we call liquid state, in air, would produce carbon dioxide, gas, and h2o gas would be to balance.
00:33
There's three here, two here, and a three here and here is our balanced equation.
00:39
For b, we have to calculate the standard enthalpy change for this reaction, assuming h2o is a gas on the product side.
00:50
So delta h -0 reaction, is equal to delta h -0 formation of the products, minus delta -h -not formation of the reactants, is it equal to 2 times delta -h -not, co2 gas, plus 3 times the delta -h -not of the gas...