We do this by dividing the mass of ethanol by its molar mass. The molar mass of ethanol ($\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}$) is $2(12.01 \, \mathrm{g/mol}) + 6(1.008 \, \mathrm{g/mol}) + 16.00 \, \mathrm{g/mol} = 46.07 \, \mathrm{g/mol}$. So, the number
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