00:01
In this problem, we are asked to draw the lewis structure for the molecule ethylopropinoid.
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Here is the chemical formula, and i'm going to draw the structure.
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I'm going to start with this c right here, and i'm going to tell you that i've got a double bond o, and then a single bond right here.
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I'll fill in my hydrogens later.
00:26
And then i've taken care of that c and that c.
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Now over on this other side, i've got another c.
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And i'll fill in all my hydrogens and my lone pairs of electrons.
00:56
There's my unbonded electrons.
00:58
So there's my lewis structure for ethyl propenoid.
01:01
That is the answer for part a.
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Part b says, how many sigma and how many pi bonds do we have? the number of sigma bonds and the number of pi bonds.
01:15
Now we're going to do the pie bonds first.
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In every double bond, there's one sigma and one pi.
01:20
I have one double bond, so i have one pi bond.
01:23
All the rest of the bonds will be single.
01:27
So i'm just going to count my lines...