00:01
So for problem 17, we're asked to find this definite integral.
00:04
And to do that, we are going to split this integral into two parts.
00:12
So this is going to be the first part, and this will be our second part.
00:17
So we're going to do another step.
00:20
We're going to move the constants in the front of the integral.
00:24
So it would be this is a constant.
00:28
This is a constant, and so is the three.
00:33
So we have 0 .4 in front of the integral of 3 to 4, e to the negative 0 .4, that should be an a, a, d -a, since we're splitting the integral.
00:57
And then we move the 3 to the front, and we have the other half of the integral, 1 over a, d -a.
01:07
So the next step would be to just figure out what the integral is.
01:18
So the integral of e to the negative 0 .4a is e to the negative 0 .4a over negative point point.
01:38
And this is evaluated from 3 to 4...