00:01
In this problem, we're going to take a look at the double integral over r of x squared minus y squared squared, da, where x is in between negative 1 and 2, and y is in between 0 and 1.
00:15
And in this particular problem, what i'm going to do is i'm just going to take this x squared minus y squared squared, and we're going to distribute this out so that the anti -derivative is a little bit easier.
00:27
So we get x to the fourth minus 2x squared, y squared plus y to the fourth.
00:37
Okay, and now our double integral will be from negative 1 to 2 and from 0 to 1 of our expanded equation.
00:50
So we have d .y and then dx.
00:55
All right, so first we're going to take the anti -derivative in terms of y.
01:00
So we have x to the 4th, y, minus 2 .5.
01:04
Two -thirds x squared y cubed plus one -fifth, y to the fifth, and we're evaluating it from y is zero to y is one...