00:01
So i am given the following information.
00:02
So all this was given.
00:07
And i need to find the tangent of data minus phi.
00:11
So all i know is that cosine of data is in quadrant three.
00:15
So it's somewhere here.
00:18
So the cosine is going to be negative, which is here.
00:22
And a sign of five is in quadrant five is in quadrant two.
00:27
So it's right here.
00:29
So the sign is positive, which i already have it.
00:32
But the cosine is negative.
00:34
So i need to know that's what i make, the adjustments that i need to make once i start to plug in stuff into my equation.
00:42
So the first thing i am going to do is use the subtraction formula for tangent.
00:47
So i know that this is going to become time of data minus tine of fi over 1 plus time of data, tan tangent of fi.
01:03
And now i don't know any of these values, but one thing that i do know is that the cosine of data is 1 over 3.
01:13
I can just ignore the negative.
01:14
I know it's negative because it's in quadrant 3, but to make the triangle to help me find the missing side, i don't need to put the negative.
01:23
So cosine of data is opposite, no adjacent over hypotenuse.
01:30
So i need to find this missing length.
01:32
So it's going to be 1 squared plus y square equals to 3 square.
01:37
This becomes 1 plus y squared equals to 9, minus 1, y squared is equal to 8.
01:47
I take the square root, which is going to leave y equals 2, the square root of 8, which then becomes 2 square root of 2.
01:59
This if you forgot breaks up into four times two so that's how i can simplify it to this i'm going to do a similar process for five again now i know that the sign it's opposite over hypotenuse so now i need to find this missing side so it's going to be one square plus x squared equals to four squared so this becomes comes 1 plus x squared equals to 16 minus 1 minus 1.
02:37
I have x squared equals to 15 and then i take the square root.
02:43
It leaves me with x equals radical 15.
02:50
So once i have all this information, i can label my missing side accordingly.
02:58
And that is going to help me, because i need to find the tangents, which i don't have yet...