First, we can rewrite the expression as a fraction of two cube roots:
$\sqrt[3]{-\frac{8}{125}} = \frac{\sqrt[3]{-8}}{\sqrt[3]{125}}$
Now, we can find the cube roots of -8 and 125:
$\sqrt[3]{-8} = -2$ (since $(-2)^3 = -8$)
$\sqrt[3]{125} = 5$ (since $5^3 =
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