Problem

Simplify:$\frac{24}{54}$

01:02

Problem 49 Hard Difficulty

Evaluate: $\frac{-4(4+2)-2^{3}}{|-12-4(5)|}$

Answer

-1

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Algebra

Elementary and Intermediate Algebra

Chapter 3

Graphing Linear Equations and Inequalities in Two Variables; Functions

Section 1

Graphing Using the Rectangular Coordinate System

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Video Transcript

operations problem here, so we're gonna need to evaluate this in the correct order. I have negative four times four plus two on top, minus 2/3 still on top, divided by absolute value bars negative 12 minus four times five and absolute value bar. Okay, so I want to remind you of Pim Dos, This is the order. We want to go in where peace parentheses e than exponents. Multiplication and division are the same level we go left to right. Same for addition and subtraction. We go left to right. Okay, so let's go ahead and start with the numerator. I'm gonna start with my parentheses. So this four plus two, that's gonna give me six minus. And I'm gonna also do the tooth to the third at the same time. That's eight. So I just did my pee in my E, and then I want to continue with parentheses and exponents on the bottom if I can, But there isn't anything, so I'll just go ahead and leave it as it iss next. I'm gonna go ahead and deal with any multiplication or division I have, and I'm gonna go from left to right. So here is some multiplication I have. So this would turn into negative 24 minus eight and on the bottom, absolute value bar stay. But I have this part right here, so we'll do. Negative. 12 minus four times five is 20. Okay, so that's all the multiplication that I can do right now. I will need to do division at the end, but I have to clean it up still before I can do that. So let's go ahead and do addition and subtraction next. So that means I'm gonna go ahead and just clear the top right up. Negative. 24 minus eight is negative. 32 and then I have absolute value. Still negative. 12 minus 20 is negative. 32. Okay, let's go ahead and take care of these parentheses, and then we'll be able to do the division. So absolute value of negative 32 on the bottom is just 32. I've done the parentheses part absolute value. Behaves like a parentheses, e. And then now I want to divide. So negative 32 divided by 32 is simply negative one. So negative one is tthe e evaluated

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