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Catherine R.

Missouri State University

Anna Marie V.

Campbell University

Kristen K.

University of Michigan - Ann Arbor

Samuel H.

University of Nottingham

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okay. What we want to dio is we want to evaluate, um, over the curve on the line integral of X y plus, why play Z d s? Um, along the curve R t is equal to to t i plus t j plus to minus two tea. Okay. And t t goes from 0 to 1 inclusive. Okay, so the first thing we need to do is we know that d s is equal to the magnitude of e of T. Um d t. And so first thing we need to do is we know that the of t is equal to the derivative, um, of that curve r t. So this is gonna be equal to two i plus J minus two K. And so, um, the magnitude of e of t is equal to the square root of t squared plus one squared plus a native to squared. And so this is gonna give me, um three. Um, and so Gs is equal to three d t. Okay, so this is gonna be the integral from 0 to 1. Um, X is to t. Why is t and Z is T minus two t and three D t so that seeing a girl we want to do, um, so this is gonna be equal to, um, three times, integral from 0 to 1. Ah, to t squared minus t plus two tt. So this is gonna be three times 2/3 t cute, minus 1/2 t squared, plus to t evaluated, um, 0 to 1. And so when we do that, um, we should get 13 house.

University of Central Arkansas
Catherine R.

Missouri State University

Anna Marie V.

Campbell University

Kristen K.

University of Michigan - Ann Arbor

Samuel H.

University of Nottingham

Lectures

Join Bootcamp