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Evaluate $\int_{-2}^{2}(x+3) \sqrt{4-x^{2}} d x$ by writing it as a sum of two integrals and interpreting one of those integrals in terms of an area.
6$\pi$
Calculus 1 / AB
Calculus 2 / BC
Chapter 5
Integrals
Section 4
The Substitution Rule
Integration Techniques
Campbell University
Harvey Mudd College
Idaho State University
Boston College
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Asian assets directly given integral as a sum of two intervals. What we know is that we can rewrite this as X plus three times four minus X squared to the power of 1/2 which means four minus X squared becomes the power of increased the exponent by one. So 3/2 been divide by the new exponents. And then this becomes X squared over two plus three. Don't forget our bounds or from negative to to to we plug n are bound, Our upper bound minus are lower bound and we end up with six pie.
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