Question
Evaluate.$$\int_{1}^{2} \frac{x^{2}-x-6}{x+2} d x$$
Step 1
The numerator $x^{2}-x-6$ can be factored into $(x+2)(x-3)$. So, the integral becomes: $$ \int_{1}^{2} \frac{(x+2)(x-3)}{x+2} d x $$ Show more…
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