00:01
112 so we have given we have to value this definite integral.
00:05
Let's call it i it we know that definite integral has a property that we can always replace.
00:10
Expire a parliament plus lower limit minus x.
00:16
So let's replace x by six minus x, while all the other things will remain same.
00:21
So the integral i can be read it and as 2 to 4, replacing x plus six minus x so the numerator will become nine minus six plus x, which is nothing but three plus x over.
00:35
Likewise, this will also become three plus x on.
00:39
This will become ah six minus x plus three is nothing but nine minus six dx.
00:45
So let's call this equation one.
00:48
Let's call this equation to if we add both the equations, we have to i s from 2 to 4.
00:56
So if you notice the denominator is actually the same.
01:00
So the numerator will be added with the common denominator.
01:03
So we have square root off ellen three per six.
01:06
Plus ellen, it's not square root off.
01:09
Ellen...