00:01
In this problem, we want to evaluate the live interval among c of x squared plus 5 squared the s, where c is a part of the circle, the part of the circle whose equation is x squared plus 5 squared equals 4 from the point 2 .0 to the point 0 .2 .2.
00:29
Now, since we are talking about a circle, we can start by parameterizing c by using r of t equals, the radius of the circle is 2, so x will equal to 2 times quosum of t, and y will equal to 2 times sine of t.
00:45
Notice that we are only referring to the part of the circle that lies in the first quadrant, for that reason, t will range from 0 to pi or 2.
00:55
Next, we continue on by finding our prime of t, which in this case we will be.
01:00
Will be negative 2 times.
01:05
And next we find the magnitude of r prime of t, which in this case will be the square root of negative 2, sine of t squared, was 2 cosine of t squared, and this simplifies down to simply 2...