Evaluate
$$
\left(\begin{array}{lll}
2 & 3 & 1 \\
0 & 1 & 5 \\
3 & 7 & 2
\end{array}\right)^{-1} \bmod 17
$$
by finding
$$
\left(\begin{array}{lll}
2 & 3 & 1 \\
0 & 1 & 5 \\
3 & 7 & 2
\end{array}\right)^{-1}
$$
(with rational entries) and then reducing each entry modulo 17.