Question
Evaluate: $\lim _{x \rightarrow 1} \frac{x^2+x-2}{x^2-1}$
Step 1
Substitute \( x = 1 \) into the expression \(\frac{x^2+x-2}{x^2-1}\). \[ \frac{1^2 + 1 - 2}{1^2 - 1} = \frac{0}{0} \] This is an indeterminate form, so we need to simplify the expression. Show more…
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